Question

Find the value of the point (1,3) 22k) are
Conjugale wer to
worto the circle x²yh
​

Answer 1

Answer:

3k = 33 or k = 11

Step-by-step explanation:

Since points (1,3) and (2,k) are conjugate w.r.t. the given circle, both the points lie on the polar of the other point.

∴(1,3) lies on x(2)+y(k)−35=0

i.e. 2×1+3×k−35=0

∴3k=33 or k=11

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