Question

Find the value of the polynomial 2y2 – 3y – 4 at (i) y = 5 (ii) y = –2.

Answer 1

Solution:

Let p(y) = 2y²-3y-4

i ) If y = 5 then

value of p(5) = 2(5)²-3(5)-4

= 50-15-4

= 50-19

= 31

ii ) if y = -2 then

p(-2) = 2(-2)²-3(-2)-4

= 8+6-4

= 10

••••

Answer 2

$\bf\huge\textbf{\underline{\underline{According\:to\:the\:Question}}}$    

p(y) = 2y² - 3y - 4

Substitute the value of p = 5

p(5) = 2(5)² - 3(5) - 4

= 50 - 15 - 4

= 50 - 19

= 31

Substitute the value of p = -2

p(-2) = 2(-2)² - 3(-2) - 4

= 8 + 6 - 4

= 10