Question

find the value of the polynomial 2yy - 8y+ 1 at y=2

Answer 1

2y^2 -8y +1

when y = 2
2(2)^2 - 8(2) + 1
2*4 - 16 + 1
8 - 16 + 1
9 - 16
- 7

Answer 2

$\textbf{Solution:}$

p(y) = 2y^2 - 8 y + 1

p(2) = 2 × (2)^2 - 8 × 2 + 1

p(2) = 8 - 16 +1

p(2) = 9 - 16

p(2) = $\textbf{-7}$

$\textbf{Thank you!!}$