find the value of the polynomial 3x^3-4x^2+7x-5 when x=3 and also when x=-3
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Answer:
3X³ - 4X² + 7X - 5
Substitute the value of X = 3 and X = -3
Step-by-step explanation:
When X = 3
3(3)³ - 4(3)² + 7(3) - 5
81 - 36 + 21 - 5 = 6
When X = -3
3(-3)³ - 4(-3)² + 7(-3) - 5
3(-27) - 4(9) + (-21) - 5
-81 - 36 -21 - 5 = - 143
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