Find the value of the polynomial 3x³-4x²+7x=5,when x=3
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Let p(x) =3x3 – 4x2 + 7x – 5
At x= 3, p(3) = 3(3)3 – 4(3)2 + 7(3) – 5
= 3×27-4×9 + 21-5 = 81-36+21-5 P( 3) =61
At x = -3, p(-3)= 3(-3)3 – 4(-3)2 + 7(-3)- 5
= 3(-27)-4×9-21-5 = -81-36-21-5 = -143 p(-3) = -143
Hence, the value of the given polynomial at x = 3 and x = -3 are 61 and -143, respectively
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