Question

Find the value of the polynomial 4+3x^3-x+2x^2 at x=0 ,x=1 ,x=-2 Please give me right solution And please do Fast

Answer 1

Answer:

f(0) = 4

f(1) = -2

f(-2) = -10

Step-by-step explanation:

$Polynomial\\f(x)=4+3x^3 - x+2x^2\\f(x)=3x^3+2x^2-x+4$

$at \ x = 0\\f(0)=3*0^3+2*0^2-0+4\\=4\\at \ x = 1\\f(1)=3*1^3+2*1^2-1+4\\=3+2-1+4=9-1=8\\at \ x = -2\\f(x)=3(-2)^3+2(-2)^2-(-2)+4\\=-3*8+2*4+2+4\\=-24+8+6=-24+14=-10$