Question

find the value of the polynomial 4x²_5x+3, when x= 2, x=½​

Answer 1

Answer:

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Answer 2

${\large{\underbrace{\underline{\bf{Question:-}}}}}$

Find the value of the polynomial 4x² - 5x + 3, when x = 2, x = ½​

${\large{\underbrace{\underline{\bf{Answer:-}}}}}$

PART - 1 (when x = 2)

Let p(x) be 4x² - 5x + 3

x = 2

∴ Substituing the value of 'x' in p(x)

4x² - 5x + 3 = p(x)

4(2)² - 5(2) + 3 = p(2)

p(2) = 4(4) - 5(2) + 3

p(2) = 16 - 10 + 3

p(2) = 6 + 3

p(2) = 9

∴ The value of p(x) ie. 4x² - 5x + 3 is 9 when x = 2

PART - 2 (when x = $\frac{1}{2}$ )

Let p(x) be 4x² - 5x + 3

x = $\frac{1}{2}[/tex}<strong> </strong></p><p>∴ Substituing the value of 'x' in p(x)</p><p>4x² - 5x + 3 = p(x)</p><p>p( [tex]\frac{1}{2}[/tex} ) = 4( [tex]\frac{1}{2}[/tex} )² - 5( [tex]\frac{1}{2}[/tex} )<strong> </strong>+ 3 </p><p>p( [tex]\frac{1}{2}[/tex} ) = 4 ( [tex]\frac{1}{4}[/tex} ) - 5( [tex]\frac{1}{2}[/tex} )<strong> </strong>+ 3 </p><p>p( [tex]\frac{1}{2}[/tex} ) = 1 - [tex]\frac{5}{2}[/tex} + 3</p><p>p( [tex]\frac{1}{2}[/tex} ) = 4 - [tex]\frac{5}{2}[/tex} </p><p></p><p>Cross multiplying --</p><p>p( [tex]\frac{1}{2}[/tex} ) = [tex]\frac{8}{2}[/tex} - [tex]\frac{5}{2}[/tex} </p><p>p( [tex]\frac{1}{2}[/tex} ) =  [tex]\frac{3}{2}[/tex}</p><p></p><p>∴<strong> The value of p(x) ie. 4x² - 5x + 3 is </strong>[tex]\frac{3}{2}$ when x = $\frac{1}{2}$

⍣ NOTE -

Only substitute the given values and carry out the operations (addition, subtraction, division,multiplication) correctly for getting perfect answer.

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