Math, asked by kalppatidar, 10 months ago

Find the value of the polynomial 5x-4r²+3 at

x=0
x= -1
x=2

Answers

Answered by Anonymous

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putting x=0

5(0)-4r²+3=0

3=4r²

√3/2=r

putting x=-1

5(-1)-4r²+3=0

-2-4r²=0

-2=4r²

√-2/2=r

putting x=2

10-4r²+3=0

13=4r²

√13/2=r

Answered by PURNA9239

Answer:

$- 4 {x}^{2} + 5x + 3 \\ here \: x = 0 \\ - 4( {0})^{2} + 5(0) + 3 \\ - 4(0) + 0 + 3 \\ 0 + 0 + 3 \\ \\ = 3 \\ \\ \\ - 4 {x}^{2} + 5x + 3 \\ here \: x = - 1 \\ \\ - 4( { - 1})^{2} + 5( - 1) + 3 \\ - 4(1) - 5 + 3 \\ - 4 - 5 + 3 \\ - 9 + 3 \\ \\ = - 6 \\ \\ - 4 {x}^{2} + 5x + 3 \\ here \: x = 2 \\ \\ - 4( {2})^{2} + 5(2) + 3 \\ - 4(4) + 10 + 3 \\ 16 + 10 + 3 \\ \\ = 29$

Step-by-step explanation:

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