find the value of the polynomial 5x-4x²+3t at (I)x=0
(ii)x= -1
(iii) x= 2
Answers
Answered by
0
Answer:
1]3t.
2]t=3
Step-by-step explanation:
5x-4x²+3t
X=0
5×0-4×0²+3t
0-0+3t
=3t
5x-4x²+3t
X=-1
5×-1-4×-1²+3t
-5-4+3t
-9+3t
t=-9/3
t=3
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Answer:
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Step-by-step explanation:
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