Question

find the value of the polynomial 6t^2+7t-3 when t= -1​

Answer 1

Answer:

-4

Step-by-step explanation:

Since t=-1

Therefore,

6t²+7t-3 = 6((-1)²)+7(-1)-3

6t²+7t-3 = 6-7-3

6t²+7t-3 = -4

Answer 2

Answer:

$4$

Step-by-step explanation:

$6 {t}^{2} + 7t - 3 = 6 {t}^{2} + 9t - 2t - 3 \\ = 3t(2t + 3) - 1(2t + 3) \\ = (2t + 3)( 3t - 1) \\ = (-2+3)(-3-1) \\ =(-1)(-4) \\ =4$

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