Question

find the value of the polynomial 6y^2+y-2 at y=1/2​

Answer 1

Answer:

= 6 ×(1/2 )^2 +1/2 -2

= 6×1/4 -3/2

= 3/2 -3/2

= 0

Answer 2

Answer:

$given \: that \: \\ y = \frac{1}{2} \: \\ so \: we \: put \: the \: value \: of \: y \: in \: the \: given \: equatin \\ 6( \frac{1}{2} )² + \frac{1}{2} - 2 \\ \frac{6}{4} + \frac{1}{2} - \frac{2}{1} \\ = > \frac{6+ 2 - 8}{4} \\ = > \frac{0}{4} \: \:= 0 answer..$

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