find the value of the polynomial at indicates value of variables p(y)=3y3-4y+√11 at y=2
Answers
Given: The polynomial p(y) = 3y³ - 4y + √11
To find: The value of the polynomial at indicates value of variables p(y) = 3y³ - 4y + √11 at y = 2
Solution:
- Now the given polynomial is:
p(y) = 3y³ - 4y + √11
- Putting y = 2, we get:
p(2) = 3(2)³ - 4(2) + √11
p(2) = 3(8) - 8 + √11
p(2) = 24 - 8 + √11
p(2) = 16 + √11
Answer:
So the value of the given polynomial at x = 2 is 16 + √11.
we have to find the value of the polynomial at indicates value of variables p(y) = 3y³ - 4y + √11 at y = 2
solution : polynomial is , p(y) = 3y³ - 4y + √11
putting y = 2 in polynomial p(y) we get,
p(2) = 3(2)³ - 4(2) + √11
= 3 × 8 - 8 + √11
= 24 - 8 + √11
= 16 + √11
Therefore the required answer is (16 + √11)