Math, asked by Anonymous, 9 months ago

find the value of the polynomial at indicates value of variables p(y)=3y3-4y+√11 at y=2​

Answers

Answered by Agastya0606
19

Given: The polynomial p(y) = 3y³ - 4y + √11

To find: The value of the polynomial at indicates value of variables p(y) = 3y³ - 4y + √11 at y = 2​

Solution:

  • Now the given polynomial is:

                    p(y) = 3y³ - 4y + √11

  • Putting y = 2​, we get:

                    p(2) = 3(2)³ - 4(2) + √11

                    p(2) = 3(8) - 8 + √11

                    p(2) = 24 - 8 + √11

                    p(2) = 16 + √11

Answer:

                 So the value of the given polynomial at x = 2 is 16 + √11.

Answered by abhi178
11

we have to find the value of the polynomial at indicates value of variables p(y) = 3y³ - 4y + √11 at y = 2

solution : polynomial is , p(y) = 3y³ - 4y + √11

putting y = 2 in polynomial p(y) we get,

p(2) = 3(2)³ - 4(2) + √11

= 3 × 8 - 8 + √11

= 24 - 8 + √11

= 16 + √11

Therefore the required answer is (16 + √11)

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