find the value of the polynomial at the indicated values of variables p(x)=3x^3+2x-3x^2+4;x=2,-2
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Answer:
p(2) =20, p(-2) =-36
Step-by-step explanation:
when x=2
p(2)=3(2^3)+2(2)-3(2^2)+4
p(2)=3(8)+4-3(4)+4
p(2)=24+4-12+4
p(2)=20
when x=-2
p(-2) =3(-2^3)+2(-2)-3(-2^2)+4
p(-2)=3(-8)-4-3(4)+4
p(-2)=-24-4-12+4
p(-2)= -36
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