Question

find the value of the polynomial f(x)=x square+x-2 at x=1 and x= -1

Answer 1

Given,

p(x) = x^2+x-2

Now,

Putting the value of x = 1 in polynomial p(x), we get:

p(1) = 1^2+1-2

= 1+1-2

= 2-2

= 0

Now,

Putting the value of x = -1 in polynomial p(x), we get:

p(-1) = (-1)^2+(-1)-2

= 1-1-2

= 0-2

= -2

♠️Thank you........!!♠️

Answer 2

Step-by-step explanation:

x square = x^2

at x=1

f (x) = x^2 + x-2

f (1) = 1^2 + 1 - 2

= 1 + (-1)

= 0

at x= -1

f (x) = x^2 + x-2

f (-1) = -1^2 + (-1 -2)

= 1 + (-3)

= -2