Question

Find the value of the polynomial f(y) =6y-3y2 +3 at
1. Y=1
2.y=-1
3.y=0

Answer 1

-3y2+6y+3

-3y2+3y+3y+3

-3y(y+1)+3(y+1)

y+1=0

y=-1

Answer:

y=-1

Answer 2

Answer:

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