Find the value of the polynomial f(y) =6y- 3y2+ 3 at
(i) y = 1 (ii) y = –1 (iii) y = 0
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at y=1 f(y)=6
at y=-1 f(y)= 0
at y = 0. f(y)= 3
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Step-by-step explanation:
(1)Find the value of the polynomial f(y)=6y-3y^2 + 3 at (a)y=1 (b)y=-1 (c)y=0 (ii) If p(x)=x^2-2√2 x + 1, find p(2√2)
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