Question

find the value of the polynomial p(x)when x=3 p(x)=x2-4x+7​

Answer 1

Answer:

p(0)=0  

2

−4(0)+3=0+0+3=3

p(1)=1  

2

−4(1)+3=1−4+3=0

p(2)=2  

2

−4(2)+3=4−8+3=−1

p(3)=3  

2

−4(3)+3=9−12+3=0

We observe that P(1) and p(3) are zeroes of the polynomial.

Answer 2

Answer:

p(3)=3^2-4(3)+7

=9-12+7

p(3)=4

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