Question

find the value of the polynomial p(x)=(x-1 (×H) at p(2).​

Answer 1

Answer:

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Answer 2

Answer:

Equation is 0 at x=−1

⇒(x+1) is a factor

Quadratic is (x+α)(x+1=0)

p(−2)=2

(−2+α)(−2+1)=2

2−α=2

α=0

Polynomial is

x

2

+x=0

⇒2

2

+2=4+2=6