Question

Find the value of the polynomial p(x) = x^3 – 3x^2 – 2x + 6 at x= root 2 .

Answer 1

$\huge\mathfrak\red{YOUR ANSWER}$

p(x)=x³-3x²-2x+6

x=✓2

✓2³-3(✓2)²-2✓2)+6

2-3(2)-2✓2+6

2-6-2✓2+6

-5+6-2✓2

-1-2✓2

$<marquee>$ ●═══════════◄ HOPE IT HELPS YOU PLEASE MARK AS BRAINLIEST ►═══════════●

Answer 2

Answer:

0

Step-by-step explanation:

p(root2)=(root2)^3-3*(root2)^2-2*root2+6

            =2root2-3*2-2*root2+6

            =2root2-6-2root2+6

            =0

root2 is also the factor of the polynomial.

Hope this helps you!!

Mark me as the brainliest!!