Question

find the value of the polynomial p(x) =x^3 -6x^2+9x+7 at X+1​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

Given:-

• We need to find the value of polynomial
• We will place the value of x simply and solve the equation.

$\sf{x^3-6x^2+9x+7}$

$\sf{x+1=0}\\\sf{x= -1}$

So, placing the Equations further:-

$\sf{(-1)^3-6(-1)^2+9(-1)+7}$

$\sf{-1-6-9+7}\\\sf{-16+7}\\\sf{=-9}$

So, -9 is the answer.

Things to Note:-

• Always when attempting these questions, equate the value of x to zero
• Here, I took the x+1 equal to zero to find the value of x
• Always use BODMAS technique to simplify
• Brackets of Division, Multiplication, Addition and Subtraction is the full form
• It states that Division is the first step to be carried out
• Followed by Multiplication, Addition and at last subtraction
• If any step is not followed answer may/might be wrong.
• Odd powers:-
• Positive remains the same and Negative also remains the same
• Even powers:-
• Positive remain the same
• But negative changes to positive.

Answer 2

Given :

$p(x) = {x}^{3} - 6 {x}^{2} + 9x + 7$

Solution :

$x + 1 \: \: \: \: \: \: \: \: \: \: \: (given)$

Let x + 1 = 0

x = -1

$p(x) = {x}^{3} - 6 {x}^{2} + 9x + 7$

$p( - 1) = {( - 1)}^{3} - 6 \times {( - 1)}^{2} + 9 \times ( - 1) + 7$

$p( - 1) = - 1 - 6 \times 1 - 9 + 7$

$p( - 1) = - 1 - 6 - 2$

$p( - 1) = - 9$