Question

find the value of the polynomial p(X)=x² +5x+4 in p(-4),p(0),p(-1) .​

Answer 1

Answer:

$p( - 4) = ( - 4) {}^{2} + 5( - 4) + 4 \\ - 16 - 20 + 4 \\ - 24$

$p(0) = (0) {}^{2} + 5(0) + 4 \\ 0 + 0 + 4 \\ 4$

$p( - 1) = ( - 1) {}^{2} + 5( - 1) + 4 \\ - 1 - 5 + 4 \\ - 2$

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Answer 2

Answer:

-2

Step-by-step explanation:

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