Question

Find the value of the polynomial p(x)=x²-x+1 at x=2.​

Answer 1

=>p(x)=x²-x+1

Here,we have to find value of p(x) at p(2).

=>p(2)=(2)²-2+1

=>4-2+1

=>2+1

=>3

Thus,the value of p(x)=x²-x+1 at x=2 is 3.

Answer 2

p(x) = x²-x+1

x = 2

So,

$p(2) = {(2)}^{2} - 2 + 1 \\ \: \: \: \: \: \: \: \: \: = 4 - 1 \\ \: \: \: \: \: \: \: = 3$

p(2) = 3

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