find the value of the polynomial P(x)= x³-3x²-2x+6 at x =√2
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Given,
The given polynomial P(x) is x³-3x²-2x+6
To find,
The value of the polynomial P(x) at x =√2.
Solution,
We can simply solve this mathematical problem using the following process:
Mathematically, the value of a polynomial at a given value of the variable can be calculated by putting that value of the variable in the polynomial and solving it.
So, the value of the polynomial P(x) at x =√2 is:
P(√2) = (√2)³-3(√2)²-2(√2)+6
= 2√2 - 6 - 2√2 + 6
= 0
Hence, the value of the polynomial P(x) at x =√2 is 0.
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