Question

Find the value of the polynomial P(y)=y2-5y+6 at y=2,y=-2

Answer 1

Answer:

$1)p(y) = {y }^{2} - 5y + 6 \\ = > p(2) = {2}^{2} - 5 \times 2 + 6 \\ = > p(2) = 4 - 10 + 6 \\ = > p(2) = 10 - 10 \\ = > p(2) = 0$

$2)p(y) = {y}^{2} - 5y + 6 \\ = > p( - 2) = ( - 2) {}^{2} - 5 \times ( - 2) + 6 \\ = > p( - 2) = 4 + 10 + 6 \\ = > p( - 2) = 20$

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Answer 2

Answer:

The values are 0 & 20.

Step-by-step explanation:

Given: Polynomial $P(y)=y^{2} -5y+6$.

To find value for $y=2,-2.$

Put $y=2$ in $P(y)=y^{2} -5y+6$.

$P(2)=2^{2} -5(2)+6$

       $=4-10+6\\=0$

Now put $y=-2$ in $P(y)$.

$P(-2)=(-2)^{2} -5(-2)+6$

           $=4+10+6\\=20$

So, for $y=2,-2$ the value of $P(y)$ are $0$ & $20$ respectively.

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