Math, asked by Anonymous, 9 months ago

Find the value of the polynomial q(x) = 3x^3 – 4x + √8 at x = 2.

Answers

Answered by priyanka0506
6

3 ({2})^{3}  - 4(2) +  \sqrt{8}

3 \times 8 - 4 \times 2 +  \sqrt{8}

24 - 8 +  \sqrt{8}

16 +  \sqrt{8}

Answered by Anonymous
25

Given:-

x = 2

To find:-

q(x) = 3x^3 – 4x + √8

Answer:-

\tt {q(2) =  3( {2})^{3} - 4(2) +  \sqrt{8}}

\tt {q(2) = 3(8) - 8 +  \sqrt{8}}

\tt {q(2) = 16 +  \sqrt{8}}

\tt {q(2) = 16 + 2.82}

 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt\boxed{q(2) = 18.82}

∴ The value of q(x) = 3x^3 – 4x + √8 at

x = 2 is 18.82

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