Math, asked by Manish8103, 11 months ago

Find the value of the polynomial x^3-7x^2+5x-3 at x=1/2

Answers

Answered by Kmg13teen
3

Step-by-step explanation:

Just put x = 1/2 in the polynomial

  = {x}^{3}  - 7 {x}^{2}  + 5x - 3  \\  \\  \\ = { (\frac{1}{2}) }^{3}  - 7 { (\frac{1}{2}) }^{2}  +  \frac{5}{2}  - 3 \\  \\  \\  =  \frac{1}{8}  -  \frac{7}{4}  +  \frac{10}{4}  -  \frac{24}{8}  \\  \\  \\  \\  \\  =  \frac{1 - 14 + 20 - 24}{8}  \\  \\  \\  \\  \\  =   \frac{ - 17}{8}

Answered by theswaggycat1
0

Answer:

x= 1/2

(1/2)³ - 7(1/2)² + 5(1/2) - 3

1/8 - 7/4 + 10/4 - 24/8

1-14+20-24/8 = -17/8

Similar questions