Question

find the value of the polynomial x²-3x+6 (i) x= √2 (ii) X=3​

Answer 1

$\blue{ANSWER:}$

(i) 8-3√2

(ii) 6

Step-by-step explanation:

Let p(x) = x²-3x +6

(i) p(√2) = (√2)² -3(√2) +6

= 2-3√2 +6

= 8 -3√2

(ii) p(3) = (3)²-3(3) +6

= 9 -9 +6

= 6

Answer 2

Answer:

The answer is  $8 - 3\sqrt{2}$ and 6 respectively.

Step-by-step explanation:

The value of the given polynomial can be easily after putting the respective given value of x in each case.

Therefore we have the following polynomial;

$x^{2} - 3x + 6$

In the first among the two cases we have,

1) x = $\sqrt{2}$

$x^{2} -3x +6$

= $(\sqrt{2})^{2} - 3(\sqrt{2} ) +6$

= 2 $-3\sqrt{2}$ + 6

= 8 $-3\sqrt{2}$

2) x = 3

$x^{2} -3x + 6$

= $3^{2} - 3(3) + 6$

= 9 - 9 + 6

= 6

Therefore the answers are $8 - 3\sqrt{2}$ and 6