Math, asked by vrushali2019, 1 year ago

Find the value of the polynomial x³–3x+6 at x=√2

Answers

Answered by cosmologist9
1

Answer:

6-√2

Step-by-step explanation:

x³=2√2

-3x= -3√2

So, value is

2√2 -3√2 +6

= -√2+6

=6-√2

Hope this will help you !

Hope this will help you !Good Luck

Answered by RagaviRagavendra
0

Heya

x {}^{3}  - 3x + 6 \\ if \: x =  \sqrt{2}  \\ then \:  substitute \: it \: in \: the \: given \: equation \\ ( \sqrt{2} ) {}^{3}  - 3( \sqrt{2} ) + 6 \\ 2 \sqrt{2}  - 3 \sqrt{2}  + 6 \\  =  -  \sqrt{2}  + 6 \\ =   -  \sqrt{2} (1 - 3 \sqrt{2} )

Hope it helps you


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