Find the value of the polynomial y^3 - 5y^2 - 6y + 9 at y = −1
Answers
Answered by
1
Answer:
the value of the polynomial y^3 - 5y^2 - 6y + 9 at y = −1 is
=(-1)³-5(-1)²-6(-1)+9
=-1-5+6+9
=-6+6+9
=9
Answered by
0
Answer:
at y= -1
y^3-5y^2 -6y +9
= (-1) ^3-5(-1) ^2-6(-1) +9
= -1-5+6+9
= 9
Similar questions