Find the value of the polynomials x3-2x2+3x+5 at (1)x=0 (2)x=1 (3)x=-2
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Given polynomial : p(x) = x³ - 2x² + 3x + 5
We need to put the following values of x and find the values:
(1) x = 0
(2) x = 1
(3) x = -2
Answer :-
(1) When x = 0,
p(0) = (0)³ - 2*(0)² +3*(0) + 5
⇒p(0) = 0 - 0 + 0 + 5
⇒p(0) = 5
(2) When x = 1,
p(1) = (1)³ - 2*(1)² +3*(1) + 5
⇒p(1) = 1 - 2 + 3 + 5
⇒p(1) = 7
(3) When x = -2,
p(-2) = (-2)³ - 2*(-2)² +3*(-2) + 5
⇒p(-2) = -8 - 8 - 6 + 5
⇒p(-2) = -17
Answered by
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Question:
Find the value of the polynomials x³-2x²+3x+5 at
(1) x= 0
(2) x= 1
(3) x= -2
Solution:
Let p(x) = x³ -2x² +3x +5
(1) For x = 0
p(0) = (0)³ -2(0)² +3(0) +5
p(0) = 0 + 5
p(0) = 5
(2) For x = 1
p(1) = (1)³ -2(1)² +3(1) +5
p(1) = 1 -2 + 3 +5
p(1) = 9 - 2
p(1) = 7
(3) For x = -2
p(-2) = (-2)³ -2(-2)² +3(-2) +5
p(-2) = -8 (-2×4) -6 +5
p(-2) = -8 -8 -6 +5
p(-2) = -17
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