Find the value of the product...
(3m-2n)(2m-3n) at m =1, n= 1
Answers
Answered by
34
Hello...
Answer....
We have,
(3m-2n) (2m-3n)
= 3m ( 2m-3n) -2n (2m-3n)
= 3m × 2m - 3m × 3n - 2n × 2m + 2n × 3n
= 6m² - 9mn - 4mn + 6n²
= 6m² - 13mn + 6n²
When m = 1, n = -1, we get
(3m -2n ) (2m - 3n)
= 6m² - 13mn + 6n²
= 6 × (1)² - 13 × 1 × (-1) + 6 × (-1)² = 6 + 13 + 6 = 25
Hope it helped
☺☺☺☺
Answer....
We have,
(3m-2n) (2m-3n)
= 3m ( 2m-3n) -2n (2m-3n)
= 3m × 2m - 3m × 3n - 2n × 2m + 2n × 3n
= 6m² - 9mn - 4mn + 6n²
= 6m² - 13mn + 6n²
When m = 1, n = -1, we get
(3m -2n ) (2m - 3n)
= 6m² - 13mn + 6n²
= 6 × (1)² - 13 × 1 × (-1) + 6 × (-1)² = 6 + 13 + 6 = 25
Hope it helped
☺☺☺☺
Answered by
11
HERE IS THE ANSWER TO YOUR QUESTION!!
We have;
(3m-2n) (2m-3n)
=> 3m ( 2m-3n) -2n (2m-3n)
=> 3m × 2m - 3m × 3n - 2n × 2m + 2n × 3n
=> 6m² - 9mn - 4mn + 6n²
=> 6m² - 13mn + 6n²
When m = 1, n = -1, we get
(3m -2n ) (2m - 3n)
=> 6m² - 13mn + 6n²
= 6 × (1)² - 13× 1× (-1) +6 × (-1)² = 6 + 13 + 6 = 25
HOPE IT HELPED!!
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