Find the value of the product for a = 1, b = 2 and c = 3.
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Step-by-step explanation:
(4a
2
+3b)(9b
2
+4a)
=36a
2
b
2
+27b
3
+16a
3
+12ab
Put the value of a=1 and b=−2, we get
(4a
2
+3b)(9b
2
+4a)
=36×(1)
2
×(−2)
2
+27×(−2)
3
+16×(1)
3
+12×(1)×(−2)
=36×4−27×8+16×1−12×2
=144−216+16−24=−80
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