find the value of the question
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what's this I don't know
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Answer:A²=-2I
C=(32+A²)/2
now A^5 - 2A³C +BA²-2BC =0 ..putting the value of C given above we get
A³=B
now i/5(B-A)² = (A³-A)²
now given A²= -2I
putting this value we get 1/5(B-A)² =1/5{det(4I²+2I)} =1/5{det(4I-2I)} =1/5{det(2I)}
=4/5
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A
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