Math, asked by kondaveetijyotsna200, 7 months ago

find the value of the question​

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Answered by lalithashrie5
0

Answer:

what's this I don't know

Answered by krishmental129
0

Answer:A²=-2I

C=(32+A²)/2

now A^5 - 2A³C +BA²-2BC =0 ..putting the value of C given above we get

A³=B

now i/5(B-A)² = (A³-A)²

now given A²= -2I

putting this value we get 1/5(B-A)² =1/5{det(4I²+2I)} =1/5{det(4I-2I)} =1/5{det(2I)}

=4/5

Step-by-step explanation:

A

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