Question

Find the value of the recangle : AB = X+3y BC= 7 CD= 15 DA = 3x+ y​

Answer 1

Answer:

y=19/4

x=3/4

Step-by-step explanation:

SINCE,

AB=CD

(opposite side of rectangle r equal)

therefore

x+3y=15

x=15-3y ------------eq.1

similarly

BC=DA

(opposite side of rectangle r equal)

therefore

3x+y=7 (from eq.1)

3(15-3y) + y=7

45-9y +y =7

-8y=7-45

-8y=-38

y=38/8

y=19/4*********

and therefore

in eq.1

x=15-3y

x=15-3(19/4)

x=15-57/4

x=60/4 - 57/4

x=3/4**********