Find the value of the shaded portion
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the area enclosed by the fig of circle is equal to one circle of radius 5cm
so
πr²
22/7×5×5=25*22/7=550/7
area of triangle
1/2base*hieght
1/2*20*10=100
ignoring the small gap (as calculation will become difficult if required inbox me i will tell you)
100-550/7
=700-550/7
=150/7
=21.4(approx)
so
πr²
22/7×5×5=25*22/7=550/7
area of triangle
1/2base*hieght
1/2*20*10=100
ignoring the small gap (as calculation will become difficult if required inbox me i will tell you)
100-550/7
=700-550/7
=150/7
=21.4(approx)
mahi2986:
answer is wrong
that might be due to the area left or my oral calculation i will text you back tomorrow for the correct answer
ok
Can you tell me the real answer
19.504
ok thanks
Answered by
1
given ,
length of the rectangle=20
breadth of the rectangle=10
area=length×breadth
=20×10
=200
Length of the rectangle=diameter of 2 circle
therefore,
area of two circle=πr²
=3.14×20/2(for two circles)
=3.14×10
=31.4
the diagonal divides the rectangle into 2 equal parts
so, the area=200/2
=100
the shaded portion=100-r
=100-5
=95
It is very hard...but I tried my best....if it is correct please mark it BRAINLIEST
length of the rectangle=20
breadth of the rectangle=10
area=length×breadth
=20×10
=200
Length of the rectangle=diameter of 2 circle
therefore,
area of two circle=πr²
=3.14×20/2(for two circles)
=3.14×10
=31.4
the diagonal divides the rectangle into 2 equal parts
so, the area=200/2
=100
the shaded portion=100-r
=100-5
=95
It is very hard...but I tried my best....if it is correct please mark it BRAINLIEST
no it's wrong
the answer should be 19.504
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