Math, asked by krishnanshu3, 1 year ago

Find the value of the sum of all 3 digit numbers which leave remainder 2, when divided by 5.

Answers

Answered by kuldeep147
1
the answer is given here thanx.
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Answered by armaanbarak
1
first three numbers numbers divided by 5= 100, 105 , 110
if the nos leave a remainder of two it would be 2 more than the no. divisible by 5. so, 102.107,112
sum= 102+107+112
       =  321
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