find the value of the unknown exterior angle ACD in the following figure
a. angle A = Angle B - 25°
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In triangle ACD
angle ACB = 130°
and AD is a straight line , so it will make an angle of 180°
So, we can say
angle ACB + angle ACD = 180°
130 + angle ACD = 180
angle ACD = 180 - 130
angle ACD = 50 °
ANOTHER METHOD
We know that in a Triangle an exterior angle is equal to sum of 2 opposite angles
so, angle BAC + angle ABC = angle ACD
25° + 25 ° = angle ACD
25° + 25 ° = 50°
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