Question

find the value of the unknown interior angle X in the following figure.anyone knows

Answer 1

we know that sum of angles in a triangle= 180

in ΔABC = ∠A+∠B+∠C=180

50 + 90+∠C=180

∠C= 180-140=40

IN ΔEDC,

∠E+∠D+∠C = 180

100 +X+∠C= 180

X+100+40=180

X= 40

Answer 2

Consider triangle ABC

By angle sum property

Angle c=180-(90+50)

=180-140=40

Consider triangle CED

100+40+x=180

X=180-140

X=40