Question

Find the value of the vertices of the triangle formed by the lines representing the equations x+y=5, x-y=5 and x=0.

CORRECT ONE WILL BE MARKED AS BRAINLIEST!!!!

Answer 1

The answer is given below :

The three lines are

x + y = 5 ...(i)
x - y = 5 ....(ii)
x = 0 ...(iii)

Adding (i) and (ii), we get

x + y + x - y = 5 + 5

⇒ 2x = 10

⇒ x = 5

From (i), we get

5 + y = 5

⇒ y = 0

So, the intersection of (i) and (ii) no. lines be (5, 0)

Putting x = 0 in (i), we get

0 + y = 5

⇒ y = 5

So, the intersection of (i) and (iii) no. lines be (0, 5)

Putting x = 0 in (ii), we get

0 - y = 5

⇒ y = - 5

So, the intersection of (ii) and (iii) no. lines be (0, - 5)

Hence, the vertices of the triangle bounded by the given lines are (5, 0), (0, 5) and (0, - 5)

[Check out the attachment for the required triangle.]

I hope it helps you.