Math, asked by Saurabhsrivastava, 1 year ago

Find the value of the x

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Answered by ranjitsingh020pbuo8j
1
hey I have solved it.
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Answered by TiwariVaishnavi
1
Here's your Answer mate....

By the Splitting middle term method ..

we get..
 \sqrt{2 {x}^{2} }  + 7x + 5 \sqrt{2}  \\  \\   = \sqrt{2 {x}^{2} }  + 2x + 5x + 5 \sqrt{2}  \\  \\  =  \sqrt{2x} (x +  \sqrt{2} ) + 5(x +  \sqrt{2)}
 = ( \sqrt{2x}  + 5)(x +  \sqrt{2) }   = 0
So the value of x is

 - 5 \sqrt{2}  \: and \:  -  \sqrt{2}

Hope it Helps!!


TiwariVaishnavi: did u get it?
Saurabhsrivastava: no
TiwariVaishnavi: its simple
Saurabhsrivastava: i know
Saurabhsrivastava: thanks
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