find the value of theta if 2sin^2theta
=1 by 2
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Value of θ if 2sin²θ = 1/2 is nπ ± π/6 , Principal Values are ± π/6 ( ± 30°)
Given:
- 2sin²θ = 1/2
To Find:
- Value of θ
Solution:
Step 1:
Divide both sides by 2
sin²θ = (1/2)(1/2)
sin²θ = (1/2)²
Step 2:
Use sin (π/6) = 1/2 and
Use Identity if sin²θ = sin²α then θ = nπ ± α
Hence
θ = nπ ± π/6
Value of θ if 2sin²θ = 1/2 is nπ ± π/6
Principal Values are ± π/6 or ( ± 30°)
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