Question

find the value of theta if ab is equals to 20 cm and BC is equals to 20 root 3 cm ​

Answer 1

Answer:

let theta be A

applying tan A

tan A =20/20√3

tan A =1/√3

tan A = tan 30

A =30

hence theta is 30

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Answer 2

The value of theta is 30°

Step-by-step explanation:

here ,

in triangle ABC,

AB = 20 cm

BC = 20√3 cm

then we have to find the value of $\theta$

using trigonometry functions

$tan \theta = \frac{perpendicular}{base}$

here , perpendicular = 20 cm

base = 20√3 cm

then

$tan \theta = \frac{20}{20\sqrt{3} } \\tan \theta = \frac{1}{\sqrt{3} } \\tan \theta = tan 30\\\theta = 30$

hence ,

The value of theta is 30°

#Learn more:

Ind the area of rhombus one of whose diagonals measures 8 cm and the other 10 cm.

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