Find the value of theta lying between 0 and 360 when tan theta = -2.0145
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SOLUTION
TO DETERMINE
The value of θ lying between 0° and 360° when
tan θ = - 1
EVALUATION
Here it is given that
tan θ = - 1
Since tan θ is negative
So θ lies in 2nd or 4 th quadrant
When θ lies in 2nd quadrant
tan θ = - 1
⇒ tan θ = - tan 45°
⇒ tan θ = tan ( 180° - 45° )
⇒ tan θ = tan 135°
FINAL ANSWER
θ = 135° , 315°
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