Question

find the value of theta when sin∅ + cos∅ = √2cos∅ (∅ ≠ 90°)​

Answer 1

Answer:

$= > \sin( \infty ) + \cos( \infty ) = \sqrt{2} \ \cos( \infty ) \\ = > \sin( \infty) = \sqrt{2} \cos( \infty ) - \cos( \infty ) \\ = > \sin( \infty ) = \cos( \infty ) ( \sqrt{2} - 1) \\ = > \sin( \infty ) = sin(90 - \infty ) ( \sqrt{2} - 1) \\ = > \infty =90 - \infty (1.414 - 1) \\ = > \infty = 90 - \infty (.414) \\ = > \infty = 90 - 0.414 \infty \\ = > \infty + \infty (0.414) = 90 \\ = > \infty (1 + 0.414) = 90 \\ = > \infty (1.414) = 90 \\ = > \infty = 90 \div 1.414 \\ = > \infty = 63.64 < ans>$

(/infty = theta )

THETA = 63.64