Question

find the value of theunknown x in the following diagrams

Answer 1

[By angle sum Prpty of triangle]

(1)180°-(50+60)°
=180-110=70°

(2)
x=180°-(90°+30°)
=180°-120°=60°

(3)
x=180°-(110+30)°
=180°-140°=40°

(4)
180°=x+x+50°
→180°=2x+50°
→180°-50°=2x
→2x=130°
→x=130/2=65°


Hope it helps...
Regards,
Leukonov.

Answer 2

a)50°+60°+x=180° as sum of all the angles is 180°
110°+x=180°
x=180°-110°
x=70°
b)30°+90°+x=180°
120°+x=180°
x=180°-120°
x=60°
c)30°+110°+x=180°
140°+x=180°
x=180°-140°
x=40°
d)50°+x+x=180°
50°+2x=180°
2x=180°-50°
2x=130°
x=130°/2
x=65°