Find the value of this equation:-
3/(x+1)+1/(x-3)=4/(x-2)
Please answer quick
Answers
Answer:
We need to find the value of x
3/x-1+1/x-3=4/x-2
On taking LCM in LHS we get
3(x-3) + 1 (x-1) / (x-1)(x-3)= 4/ x-2
=>3x-9 + x-1 / (x-1)(x-3) = 4/ x-2
=> (4x -10) (x-2) = 4 (x-1) (x-3)
= >4×2 – 8x -10x+20= 4 (x2 -3x -x+3)
=> 4x2 -18x +20 = 4x2 – 12x -4x +12
=> 4x2 -18x +20 = 4x2 – 16x +12
4x2 gets cancelled on both sides
=> -18x +20 = – 16x +12
=> -18x+16x = 12 – 20
=> -2x = -8
Negative sign gets cancelled on both sides
=> 2x= 8
=> x= 8/2
=>x=4
Hence x=4
Answer:
x = 4
Step-by-step explanation:
3/x-1+1/x-3=4/x-2
We need to find the value of x
3/x-1+1/x-3=4/x-2
On taking LCM in LHS we get
3(x-3) + 1 (x-1) / (x-1)(x-3)= 4/ x-2
=>3x-9 + x-1 / (x-1)(x-3) = 4/ x-2
=> (4x -10) (x-2) = 4 (x-1) (x-3)
= >4×2 – 8x -10x+20= 4 (x2 -3x -x+3)
=> 4x2 -18x +20 = 4x2 – 12x -4x +12
=> 4x2 -18x +20 = 4x2 – 16x +12
4x2 gets cancelled on both sides
=> -18x +20 = – 16x +12
=> -18x+16x = 12 – 20
=> -2x = -8
Negative sign gets cancelled on both sides
=> 2x= 8
=> x= 8/2
=>x=4
Hence x=4