find the value of this..
pls show the process
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FIRSTLY
SUM OF SQUARES OF FIRST 50 NUMBERS :
n(n+1)(2n+1)/6
=50(50+1)(100+1)/6
=50(51)(101)/6
=50×51/6×101
=42925.
then,
SUM OF SQUARES OF FIRST 5 NUMBERS:
=5(5+1)(10+1)/6
=5(6)(11)/6
=55.
SUM OF SQUARES OF NUMBERS FROM 6 TO 50:
=42925-55
=42879
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