Question

find the value of this ques.

Answer 1

let [cos^(-1) 7/25]=A,

then
cosA=7/25,

then by Pythagoras theorem,
perpendicular=24,

then

cotA=7/24

Answer 2

cot(cos^-1(7/25))

take cos^-1(7/25) = S

then

cos S = 7/25..


we know That sin^2 theta + cos^2 theta = 1

sin^2 theta = 1 - cos^2 theta

sin theta = √(1 - cos^2 theta)

here theta = S..substituting 7/25

sin S = √(1 - (7/25)^2)


cos^-1(7/25) is taken as S

so cot(cos^-1(7/25)) = cot S

we know That Cos S/Sin S

= (7/25)/ √(1 - (7/25)^2)

= (7/25)/ √(1 - 49/625)

= (7/25)/ √((625-49)/625)

= (7/25)/ √((576)/625))

=(7/25)/ √((576)/625))

√576 = 24 ; √625 = 25


=(7/25)/ (24/25)

=7/24