Question

find the value of this question

Answer 1

$\cos(theta) = m \div n$
$\sin(thita) = \sqrt{1 - { \cos(thita) }^{2} }$
$\sin(thita) = \sqrt{1 - {m}^{2} \div {n}^{2} }$
$\: \: \: \: \: = \sqrt{ {n}^{2} - {m}^{2} \div {n}^{2} }$
$\tan(theta) = \sin(theta) \div \cos(theta)$
$\tan(theta) = m \div \sqrt{ {n}^{2} - {m}^{2} }$
i hope this help u.
thanks