Question

Find the value of this question​

Answer 1

Answer:

Step-by-step explanation:

$\frac{sin^{2}22+sin^{2}68 }{cos^{2} 22+cos^{2}68 } +sin^{2}63+cos63 sin27$

$=[\frac{sin^{2}22+sin^{2}(90-22) }{cos^{2}22+cos^{2}(90-22) } +sin^{2}63+cos63\timessin(90-63)]$

$= \frac{sin^{2}22+cos^{2}22 }{cos^{2}22+sin^{2}22 } +sin^{2}63+cos^{2}63$

$=1+1$

$= 2$

Answer 2

Answer:

the answer is write dii

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